We show that if there are no three consecutive powerful numbers then there is an infinite sequence of primes p for which p2 does not divide 2p−2, and so the first case of Fermat's Last Theorem is true for exponent p.
We show that if the first case of Fermat's Last Theorem is false for prime p then p divides the numerator of Bp−1−n for all integers n≤(logp/loglogp)1/2.